Question

In right angle triangle $\Delta PQR,$ right angle is at $Q$ and $PQ=6cm,\angle RPQ={60}^{\circ }.$ Determine the lengths of $QR$ and $PR.$

Answer 1

$Fromtheabovefigure$

$PR\cos {60}^0=6$

$\therefore PR=\left(\frac{6}{cos{60}^0}\right)=12$

$QR=PR\sin {60}^0$

$=12\times \left(\frac{\sqrt{3}}{2}\right)=6\sqrt{3}$