In Ruchika's wallet there are Rs. 16 , which consisting 10 paise , 20 paise and Re. 1 coins . The ratio of 10 paise coins and 20 paise coins is 6: 1 . The maximum no . of Re 1 coin is:

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Solution

The correct option is D 9
Let the no. of 10 paise and 20 paise coin be $6 x$ and $x$

Let the number of coin of Re 1 be $y$

$\therefore 6x+x+y=16\\\implies y=16-7x
for x=1, we have $y = 9$

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In Ruchika's wallet there are Rs. 16 , which consisting 10 paise , 20 paise and Re. 1 coins . The ratio of 10 paise coins and 20 paise coins is 6: 1 . The maximum no . of Re 1 coin is:

The correct option is D 9Let the no. of 10 paise and 20 paise coin be 6x and xLet the number of coin of Re 1 be y$\therefore 6x+x+y=16\\\implies y=16-7xfor x=1, we have y=9

The correct option is D 9
Let the no. of 10 paise and 20 paise coin be $6 x$ and $x$

Let the number of coin of Re 1 be $y$

$\therefore 6x+x+y=16\\\implies y=16-7x
for x=1, we have $y = 9$