In square PQRS if PQ=3x−7 and QR=x+3, Find PS
10
8
6
12
Sides of a square are equal.
PQ=QR
⇒3x−7=x+3
⇒3x−x=3+7
⇒2x=10
⇒x=5
⇒PS=QR=x+3=5+3=8
In square PQRS if PQ=(3x−7) units and QR=(x+3) units, Find PS.
In square PQRS :(i) if PQ=3x−7 and QR=x+3 ; find PS(ii) if PR=5x and QR=9x−8. Find QS