Question

Question 17

In standard form, the number 829030000 is written as $K\times {10}^8,$ where $K$ is equal to:
(a) 82903
(b) 829.03
(c) 82.903
(d) 8.2903

Answer 1

We have,
A number in the standard form is written as $K\times {10}^8,$ then $K$ will be a terminating decimal such that $1\le K\le 10.$
So, there is only one option, where $K=8.2903<10$