In Sulphur estimation $0.157$ grams of an organic compound gave $0.4813$ gram of barium sulphate. what is the percentage of Sulphur in the compound?

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Solution

weight of sulphur is 32 u
and weight of $B a S O_{4}$ is 233 u
so weight of sulphur in $B a S O_{4} = \frac{32}{233} \times 0.4813$

percentage of suphur $= \frac{32}{233} \times \frac{0.4813}{0.157} \times 100 = 42.10 %$

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In Sulphur estimation 0.157 grams of an organic compound gave 0.4813 gram of barium sulphate. what is the percentage of Sulphur in the compound?

weight of sulphur is 32 uand weight ofBaSO4 is 233 uso weight of sulphur inBaSO4=32233×0.4813percentage of suphur=32233×0.48130.157×100=42.10%

In Sulphur estimation $0.157$ grams of an organic compound gave $0.4813$ gram of barium sulphate. what is the percentage of Sulphur in the compound?

weight of sulphur is 32 u
and weight of $B a S O_{4}$ is 233 u
so weight of sulphur in $B a S O_{4} = \frac{32}{233} \times 0.4813$

percentage of suphur $= \frac{32}{233} \times \frac{0.4813}{0.157} \times 100 = 42.10 %$