In $T - 20$ cricket match, Raju hit a Six $10$ times out of $50$ balls he played. If a ball was selected at random find the probability that he would not have hit a Six

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Solution

Total Number of balls Raju faced $= 50$ i.e., $n = 50$
Let $E$ be the event of hit a "Six" by Raju
$n (E) = 10$ i.e., $m = 10$
$P (E) = \frac{Number of times Raju hits a "Six"}{Total number of balls faced}$
$= \frac{m}{n} = \frac{10}{50} = \frac{1}{5}$
$P$ (Raju does not hit a Six) $= P (E^{'}) = 1 - P (E)$
$= 1 - \frac{1}{5} = \frac{4}{5}$

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In T−20 cricket match, Raju hit a Six 10 times out of 50 balls he played. If a ball was selected at random find the probability that he would not have hit a Six

Total Number of balls Raju faced =50 i.e., n=50Let E be the event of hit a "Six" by Rajun(E)=10 i.e., m=10P(E)=Number of times Raju hits a "Six"Total number of balls faced=mn=1050=15P(Raju does not hit a Six) =P(E′)=1−P(E)=1−15=45

In $T - 20$ cricket match, Raju hit a Six $10$ times out of $50$ balls he played. If a ball was selected at random find the probability that he would not have hit a Six