In the above figure AB || CD. Also, ∠EAB = 84o and ∠ECD = 126o. Then, the value of "x" is
150o
Draw EF parallel to both AB and CD
∠BAE + ∠AEF = 180o (consecutive interior angles are supplementary)
∠AEF = 180o - 84o = 96o
Similarly, FEC = 180o - 126o = 54o
Hence x = 96o + 54o = 150o