∠ACD=90∘ [Tangent at any point of a circle and the radius through this point are perpendicular to each other)
∠ACD=∠ABC=90∘ [Angles in alternate segments are equal]
The angle between a tangent and a chord through the point of contact is equal to an angle in the alternate segment.
Consider ΔABC,
∠BAC+∠ACB+∠ABC=180∘
60∘+∠ACB+90∘=180∘ [Given, ∠BAC=60∘]
∠ACB=180−150∘∠ACB=30∘
∴ Options (a), (b), (c) are true.