Question

In the above figure where O is the center of the circle, AB=CD and $\angle AOB={30}^{\circ }.$ Then, $\angle AED$ = and $\angle COD$ = .

• A. 90°
• B. 50°
• C. 40°
• D. 30°

Answer 1

Answer: (A), (D)

30°

Given that $AB=CD.$ We know that equal chords subtend equal angles at the centre.
$⟹\angle AOB=\angle COD={30}^{\circ }$
Also, we know that angle in a semicircle is a right angle.
$⟹\angle AED={90}^{\circ }$
$\therefore \angle AED={90}^{\circ }$and $\angle COD={30}^{\circ }$