In the above question, if both are in opposite direction, then the velocity of the pulse with respect to ground will be:
A
ωL
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B
ωL2π
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C
ωLπ
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D
\N
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Solution
The correct option is D \N Velocity of rope w.r.t. ground will be VRG=ωR=−ωL2π ( Negative sign indicates that pulse velocity and rope velocity are in opposite direction)
As obtained in the previous question, the velocity of pulse w.r..t. rope is given by, VPR=ωL2πVPR=VPG−VRG=ωL2π⇒VPG−−ωL2π=ωL2π∴VPG=0