In the above question, if the motion of the pulse and rotation of the loop, both are in same direction then the velocity of the pulse with respect to ground will be:
A
ωL
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B
ωL2π
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C
ωLπ
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D
ωL4π2
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Solution
The correct option is CωLπ Velocity of rope w.r.t. ground will be VRG=ωR=ωL2π
As obtained in the previous question, the velocity of pulse w.r..t. rope is given by, VPR=ωL2πVPR=VPG−VRG=ωL2π⇒VPG−ωL2π=ωL2π∴VPG=(wL2π)2=ωLπ