In the above reaction if A is NH4Cl and D is CO2 then B C respectively are -A - NaOH - NaCl -NH3-H2O NH3-CO2-H2O- BB -NaCl- C - NH4ClC - Na2CO3-H2O-D

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Reactivity Trends (Group 2)

In the above ...

Question

In the above reaction if $A$ is $N H_{4} C l$ and $D$ is $C O_{2}$ then $B$ & $C$ respectively are :

(A) $+ N a O H \to N a C l + N H_{3} + H_{2} O$
$N H_{3} + C O_{2} + H_{2} O \to (B)$
(B) $+ N a C l \to (C) + N H_{4} C l$
(C) $\to N a_{2} C O_{3} + H_{2} O + (D)$

N H_{4} H C O_{3}, N a H C O_{3}

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N a H C O_{3}

N H_{4} H C O_{3}

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{(N H_{4})}_{2} C O_{3}, N a_{2} C O_{3}

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N a_{2} C O_{3}, {(N H_{4})}_{2} C O_{3}

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Similar questions

2 N a C l + C a C O_{3} \to N a_{2} C O_{3} + C a C l_{2}

C a C O_{3} Δ - \to [A] + [B]

N a C l + N H_{3} + [B] + H_{2} O \to [C] + [D]

2 [C] \to N a_{2} C O_{3} + H_{2} O + [B]

(A), (B), (C)

(D)

(A) + N a O H H e a t ⟶ N a C l + N H_{3} + H_{2} O

N H_{3} + C O_{2} + H_{2} O ⟶ (B)

(B) + N a C l ⟶ (C) + N H_{4} C l

(C) H e a t ⟶ N a_{2} C O_{3} + H_{2} O + (D)

N a H C O_{3}

N a_{2} C O_{3}

H C l

15.0

11.0

N a C l

N a_{2} C O_{3}

N a_{2} C O_{3} + 2 H C l \to 2 N a C l + C O_{2} + H_{2} O

N a H C O_{3} + H C l \to N a C l + C O_{2} + H_{2} O

N a C l

N a H C O_{3}

N a_{2} C O_{3}

58.5

84

106

X

N a C l + H_{2} O + C O_{2} + N H_{3}

\to

N H_{4} C l + X

X

C O_{2} + N H_{3} + H_{2} O \to (A)

(A) + N a C l \to (B) + N H_{4} C l

(B) \to (C) + C O_{2} + H_{2} O

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