Question

In the above triangle ABC, point P is the centroid of the triangle. The length of AE is 15 cm. Find the length of AP and PE.

Answer 1

The point of intersection of all the medians (or the centroid), divides each median in the ratio 2 : 1.
So, AP : PE =2 : 1
New, AE =15
$AP=\frac{2}{3}\times 15=10cm$
$PE=\frac{1}{3}\times 15=5cm$