Question

In the adjoining figure, D is a point on the side BC of $\Delta ABC$ such that $\angle ADC=\angle BAC$ Then $\frac{CA}{CD}=\frac{CB}{CA}$

• A. True
• B. False

Answer 1

The correct option is A True

$In△ABC\&△ADC$

$⟹\angle BAC=\angle ADC=\theta$

$\angle C=\angle C$ (given)

by AAA

$\therefore △ABC\sim △ADC$

$⟹\frac{AB}{AD}=\frac{BC}{AC}=\frac{AC}{DC}$

$⟹\frac{CB}{CA}=\frac{CA}{CD}$

$\therefore$ A)True