Question

In the adjoining figure, $OACB$ is a quadrant of a circle of radius $7cm$. The perimeter of the quadrant is
Note: $\pi =\frac{22}{7}$

• A. $11cm$
• B. $18cm$
• C. $25cm$
• D. $36cm$

Answer 1

Answer: (C)

$25cm$

Perimeter $=\frac{1}{4}\times 2\pi r+2r=(\frac{1}{2}\times \frac{22}{7}\times 7+2\times 7)cm$
$=25cm$