Question

In the given figure, OACB is a quadrant of a circle with centre O and radius $3.5cm.$ If $OD=2cm$, find the area of the quadrant OACB

Answer 1

Given:-

$OACB$ is a quadrant of a circle with centre $O$ and radius $3.5cm$.

$OD=2cm$

• Area of quadrant $OACB=\frac{1}{4}\times$ Area of circle
  

$\therefore$ Area of quadrant $OACB$ $=\frac{1}{4}\times \pi r^2=\frac{1}{4}\times \frac{22}{7}\times {\left(3.5\right)}^2=9.625{cm}^2$