In the adjoining figure, the radius of the inner circles, if other circles are of radii m units is
A
(√2−1)m
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B
√2m
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C
1√2m
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D
1√2+1m
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Solution
The correct option is B(√2−1)m Join the centres of the circles such that it forms a square and the centre of the inner circle lies on the diagonal of the square. Now, each side will be 2m. Hence, the diagonal of the square will be = 2√2m Length of the radius of inner circle = 2√2m−2m2 = (√2−1)m