Question

In the arrangement shown in the figure the rod R is restricted to move in the vertical direction with acceleration $a_1$, and the block B can slide down the fixed wedge with acceleration $a_2$. The correct relation between $a_1$ and $a_2$ is given by :

• A. $a_2=a_{1}sin\theta$
• B. $a_{2}sin\theta =a_1$
• C. $a_{2}cos\theta =a_1$
• D. $a_2=a_{1}cos\theta$

Answer 1

The correct option is B $a_{2}sin\theta =a_1$

Both R and B must remain in contact.
Thus, acceleration of R and B along the vertical direction should be same.
Thus, $a_2\sin \theta =a_1$