In the arrangement shown, neglect the mass of the ropes and pulley. What must be the value of m to keep the system in equilibrium? There is no friction anywhere.
A
M
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B
2M
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C
M2
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D
M4
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Solution
The correct option is CM2 As the block m is in equilibrium ⟹mg=T′′
For the bottommost pulley, we can say T′=2T′′ and 2T=T′
( as pulleys are assumed to be light) ∴T=T′′=mg
For mass M on the inclined plane, we can say : T=Mgsin30=Mg/2 mg=Mg/2 ∴m=M/2