Question

In the balanced chemical reaction $I{O}_3^{-}+a{I}^{-}+b{H}^{+}\to c{H}_{2}O+d{I}_2$ a, b, c and d respectively correspond to

• A. 5, 6, 3, 3
• B. 5, 3, 6, 3
• C. 3, 5, 3, 6
• D. 5, 6, 5, 5

Answer 1

The correct option is A 5, 6, 3, 3

$I{O}_3^{-}+a{I}^{-}+b{H}^{+}\to c{H}_{2}O+d{I}_2$
Step 1 : $I^{-1}\to I_2\left(oxidation\right)I{O}_3^{-}\to I_2\left(reduction\right)$
Step 2: $2I{O}_3^{-}+12H^{+}\to I_2+6H_{2}O$
Step $3:2I{O}_3^{-}+12j^{+}+10e\to I_2+6H_{2}O2I^{-}\to I_2+2e$
Step 4: $2I{O}_3^{-}+12H^{+}+10e^{-}\to I_2+6H_{2}O[2I^{-}\to I_2+2e]5$
Step 5 : $2I{O}_3^{-}+10I^{-}+12H^{+}\to 6I_2+6H_{2}OI{O}_3^{-}+5I^{-}+6H^{+}\to 3I_2+3H_{2}O$
On comparing, a = 5, b = 6, c = 3, d = 3