Question

In the Bohr model of hydrogen atom, the ratio of the kinetic energy and total energy of electron in the $n^{th}$ quantum state will be

• A. $1$
• B. $-1$
• C. $2$
• D. $-12$

Answer 1

The correct option is B $-1$

Total energy in hydrogen atom $=\frac{-13.6}{n^2}eV$
Kinetic energy in hydrogen atom $=\frac{13.6}{n^2}eV$

Ratio of kinetic energy and total energy $=-1$