In the Cannizzaro reaction given below-2 Ph - CHO - - P H - CH 2 OH - PhCO 2- the slowest step is-A- The attack of OH at the carbonyl groupB- The deprotonation of P h - CH 2 OH-C- The transfer of hydride to the carbonyl group-D- The abstraction of proton from the carboxylic acid-

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The Cannizaro Reaction

In the Canniz...

Question

In the Cannizzaro reaction given below:
$2 P h - C H O ⊖ O H - - \to P H - C H_{2} O H + P h C O_{2}^{⊖}$ the slowest step is:

The attack of

⊖ O H

at the carbonyl group

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The transfer of hydride to the carbonyl group.

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The abstraction of proton from the carboxylic acid.

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The deprotonation of

P h - C H_{2} O H .

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Solution

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2 P h C H O O H^{-} - -- \to p h C H_{2} + p h C O_{2}^{-} .

P h - C H O O H^{-} - -- \to P h - C H_{2} - O H + P h C O O^{-}

2 P h - C H O - O H ⟶ P h - C H_{2} O H + P H C O_{2}^{\oplus}

2 P h - C H O ⊖ O H - - \to P H - C H_{2} O H + P h C O_{2}^{⊖}

2 P h - C H O {O H}^{-} - ---------- \to P h - C H_{2} - O H + P h C O_{2}^{-}

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