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Question

In the cannizzaro reaction given below
2Ph−CHOOH−−−−−−−−−−−−→Ph−CH2−OH+PhCO−2
the slowest step is:

A
the attack of ¯¯¯¯OH at the carbonyl group
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B
the transfer of hydride ion to the carbonyl group
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C
the abstraction of a proton from the carboxylic acid
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D
the deprotonation of PhCH2OH
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Solution

The correct option is A the transfer of hydride ion to the carbonyl group
Hydride ion transfer to the carbonyl group is the slowest or the rate determining step.
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