In the cannizzaro reaction given below 2Ph−CHOOH−−−−−−−−−−−−→Ph−CH2−OH+PhCO−2 the slowest step is:
A
the attack of ¯¯¯¯OH at the carbonyl group
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B
the transfer of hydride ion to the carbonyl group
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C
the abstraction of a proton from the carboxylic acid
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D
the deprotonation of Ph−CH2OH
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Solution
The correct option is A the transfer of hydride ion to the carbonyl group Hydride ion transfer to the carbonyl group is the slowest or the rate determining step.