In the Cannizzaro's reaction given below,

The slowest step is:

The attack of OH^- at the carbonyl group

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The transfer of hydride to the carbonyl group

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The abstraction of proton from the carboxylic acid

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The deprotonation of Ph―CH₂OH

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Solution

The correct option is B
The transfer of hydride to the carbonyl group

The slowest step is the transfer of hydride ion to the carbonyI group as shown in mechanism.

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Similar questions

P h - C H O O H^{-} - -- \to P h - C H_{2} - O H + P h C O O^{-}

2 P h - C H O ⊖ O H - - \to P H - C H_{2} O H + P h C O_{2}^{⊖}

2 P h C H O O H^{-} - -- \to p h C H_{2} + p h C O_{2}^{-} .

P h - C H O O H^{-} - -- \to P h - C H_{2} - O H + P h C O O^{-}

2 P h - C H O - O H ⟶ P h - C H_{2} O H + P H C O_{2}^{\oplus}

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