Question

In the circuit given below potential difference across 6 $\mu$ F capacitor is

• A. 8 V
• B. 4 V
• C. 6 V
• D. 3 V

Answer 1

The correct option is B 4 V

$q=C_1{V}_1=C^1{V}_2$
$\frac{V_1}{V_2}=\frac{C^1}{C_1}=\frac{9}{4.5}=\frac{2}{1}$
$\frac{V_1+V_2}{V_2}=\frac{2+1}{1}$
$V_2=\frac{12}{3}=4V$