Question

In the circuit initially switch $S$ is open the $S$ is closed at $t=0$ the difference between the maximum and minimum current that can flow in the circuit is:

• A. $2$ Amp
• B. $3$ Amp
• C. $1$ Amp
• D. Nothing can be concluded

Answer 1

The correct option is C $1$ Amp

$\begin{array}{c}Att=0inductorisopencircuited\\ Att=inity,inductorisshortcircuited\\ Att=0\\ i=\frac{10}{10}=1\\ Att=inity\\ i=\frac{10}{5}=2amp\\ Hence,difference=2-1=1amp\\ Hence,theoptionCisthecorrectanswer.\end{array}$