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Question

In the circuit shown below E1=4.0 V,R1=2 Ω, E2=6.0 V, R2=4Ω and R3=2Ω. The current l1 is
1119950_7d9651ba31bc4c07bf5fee60b4a49e38.png

A
1.6 A
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B
1.8 A
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C
1.25 A
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D
1.0 A
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Solution

The correct option is B 1.8 A
Applying Kirchhoff's law for the loops (1) and (2) as shown in figure
For loop (1)
2i12(i1i2)+4=02i1i2=2 .....(i)
For loop (2)
2(i1i2)+4i26=0i1+3i2=3 .....(ii)
On solving equation (i) and (ii) i1=1.8 A

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