Question

In the circuit shown below,


the input power factor is

• A. 0.89 lagging
• B. 0.82 lagging
• C. 0.82 leading
• D. 0.89 leading

Answer 1

The correct option is D 0.89 leading

$Y_{eq}=\frac{1}{50}+\frac{1}{j(2\pi \times 50\times 0.15)}+j(2\pi \times 50\times 100\times {10}^{-6})$

$Y_{eq}=0.0224\angle 27.01{}^{\circ }\mho$

$Z_{eq}=44.64\angle -27.01{}^{\circ }\Omega$

$I=\frac{100\angle 0{}^{\circ }}{44.64\angle -27.01{}^{\circ }}$

$=2.24\angle 27.01{}^{\circ }A$
The input power factor = cos (27.01°) = 0.89 leading.