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Question

In the circuit shown below, the key K is closed at t=0. The current through the battery is
1079633_2c350cc0684f4014a6a3f0e7f0ce9b6a.PNG

A
VR1R2R21+R22 at t=0 and VR2 at t=
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B
VR2 at t=0 and V(R1+R2)R1R2 at t=
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C
VR2 at t=0 and VR1R2R21+R22 at t=
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D
V(R1+R2)R21R2 at t=0 and VR2 at t=
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Solution

The correct option is B VR2 at t=0 and V(R1+R2)R1R2 at t=

We know that,

At t=0, inductor behave like an infinite resistance

So, at t=0

i=VR2

Now, at t=, inductor behave like conductive wire

So,

i=V(R1+R2)R1R2

Hence, the current is i=VR2 at t=0 and V(R1+R2)R1R2 at t=


1017356_1079633_ans_4f7700614e9c4d05abef63e2066b0e98.PNG

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