In the circuit shown- E 1 -7V- E 2 -7V- R 1 - R 2 -1- - R 3 -3- respectively- The current through the resistance R3 is

The correct option is A 2A According to Kirchoff's circuital law, x 71+x 71+x 03=0 ⇒ 3x+3x+x 21 21=0 ⇒ 7x=2× 21=6V Current through R_3=6 ...

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Combination of Resistances

In the circui...

Question

In the circuit shown, $E_{1} = 7 V, E_{2} = 7 V, R_{1} = R_{2} = 1 Ω, R_{3} = 3 Ω$ respectively. The current through the resistance $R_{3}$ is

2 A

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3.5 A

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1.75 A

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none of these

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Similar questions

E_{1}

E_{2} = 7 V

R_{1} = R_{2} = 1 Ω

R_{3} = 3

R_{3}

E_{1} = 7 V, E_{2} = 7 V, R_{1} = R_{2} = 1 Ω, R_{3} = 3 Ω

R_{3}

E_{1} = 4.0 V, R_{1} = 2 Ω, E_{2} = 6.0 V, R_{2} = 4 Ω

R_{3} = 2 Ω .

l_{1}

E_{1} = 17 V, E_{2} = 21 V, R_{1} = 2 Ω, R_{2} 3 Ω

R_{3} = 5 Ω

R_{1}, R_{2}

R_{3}

E_{1} = 4.0 V, R_{1} = 2 Ω, E_{2} = 6.0 V, R_{2} = 4 Ω

R_{3} = 2 Ω

I_{1}

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