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Mechanism of Formation of P-N Junction

In the circui...

Question

In the circuit shown here, $E_{1} = E_{2} = E_{3} = 2 V$ and $R_{1} = R_{2} = 4 o h m s$ . The current flowing between points $A$ and $B$ through battery $E_{2}$ is :-

A

z e r o

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B

2 a m p

from

A

to

B

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C

2 a m p

from

B

to

A

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D

n o n e o f t h e a b o v e

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Solution

The correct option is B $2 a m p$ from $A$ to $B$
Consider two mesh currents $i_{1}$ and $i_{2}$ is shown in the figure.
For top mesh: $E_{1} + E_{2} = i_{1} R_{1}$ or $2 + 2 = 4 i_{1} \Rightarrow i_{1} = 1 A$
For bottom mesh: $- E_{3} - E_{2} = i_{2} R_{2}$ or $- 2 - 2 = 4 i_{1} \Rightarrow i_{2} = - 1 A$
Net current flow from A to B is $i_{1} - i_{2} = 1 - (- 1) = 2 A$

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