Question

In the circuit shown in figure, all cells are ideal. The current through $2\Omega$ resistor is

• A. $5A$
• B. $1A$
• C. $0.2A$
• D. Zero

Answer 1

The correct option is A $5A$

$V_A=0V$

$V_C=8V$

$V_B=4V$

$V_D=2V$

i,e $=\frac{-8(-2)}{2}$

$=\frac{10}{2}$

$=5A$.