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Question

In the circuit shown in figure, I2=3A in the steady state. The potential difference across the 4Ω resistor


A
12 V
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B
18 V
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C
20 V
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D
24 V
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Solution

The correct option is C 20 V
In the steady state, the resistance of the inductor is zero, i.e. it behaves as a short circuit. Hence the circuit can be drawn as follows.

I2=3A. Therefore, p.d. across 1+3=4Ω resistance = 3×4=12V.Hence I1=126=2A. Therefore I=I1+I2=2+3=5A, which is the current flowing through 4Ω resistance. So p.d. across 4Ω resistance = 5×4=20V.

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