Question

In the circuit shown in figure the maximum output voltage $V_0$ is :-

• A. 0 V
• B. 5 V
• C. 10 V
• D. $\frac{5}{\sqrt{2}}V$

Answer 1

The correct option is B 5 V

For the positive half cycle og input the resulting network is shown below

$\Rightarrow (V_0{)}_{ma}=\frac{1}{2}(V_i{)}_{max}=\frac{1}{2}\times 10=5V$