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Question

In the circuit shown in figure, the ratio of charges on 5μF and 4μF capacitor is:
1030699_a7108e6639504104ac31f4b7cad82b12.png

A
4/5
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B
3/5
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C
3/8
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D
1/2
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Solution

The correct option is C 3/8
Potential difference across 5μF, V1 = 3106 =1.8 V
Q1 = charge at 5μF = C *V1 = 5 *1.8 = 9μC
Similarly,
Potential difference across μF , V2 = 6 V
Q2 =charge at 4μF = 4* 6 =24μF
Q1/Q2 =9/24 =3/8

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