Question

In the circuit shown in figure, the voltage drop between A and D is

• A. 10 V
• B. 5 V
• C. 4 V
• D. 6 V

Answer 1

The correct option is A 10 V

$V_C=V_B+4V$ as current in wire BC will be zero

consider $V_B=0$

using kirchoff's loop law in loop ABA

$10-2i_{ABA}-3i_{ABA}=0\Rightarrow i_{ABA}=2A$

$V_A=10-I_{ABA}2\Omega =10-2\ast 2=6V$

using kirchoff's loop law in loop CDC

$20-4i_{CDC}-6i_{CDC}=0\Rightarrow i_{CDC}=2A$

$V_C=4V$

$V_C-V_D=I_{cdc}4\Rightarrow V_D=V_C-I_{CDC}4\Omega =4-I_{CDC}4\Omega =-4V$

$V_A-V_D=6-(-4)V=10V$