In the circuit shown in figure, when the input voltage of the base resistance is 10V,Vbe is zero and Vce is also zero. Value of β is
A
133
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B
154
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C
196
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D
105
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Solution
The correct option is B133 Given Vi=10V,Rb=400kΩ=400×103Ω Rc=3kΩ=3×103Ω,Vbe=0 Vce=0,VCC=10V As Vi−Vbe=RbIb ∴10−0=(400×103)Ib Ib=10400×103=25×10−6A=25μA and VCC−Vce=IcRc Ic=103×103=3.33×10−3=3.33mA β=IcIb=3.333×10−325×10−6=133.