Question

In the circuit shown in the Figure $R_1>R_2$, in which resistance the power dissipated is greater?

• A. $R_1$
• B. $R_2$
• C. equal to both
• D. uncertain

Answer 1

Answer: (B)

$R_2$

Since, the resistors are connected in parallel to each other and the source, voltage across them is same hence the power dissipated in resistors is

$P_1=\frac{V^2}{R_1}\Rightarrow P_1\propto \frac{1}{R_1}$

and

$P_2=\frac{V^2}{R_2}\Rightarrow P_2\propto \frac{1}{R_2}$

Given that $R_1>R_2$ therefore

$P_1<P_2$

Hence, the power dissipated is greater in $R_2$