In the circuit shown in the figure, the heat produced it is the 5 Ω resistor due to the current flowing through it is 10 calories per second. The heat generated in the 4 Ω resistor is
A
1 calories/sec
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B
2 calories/sec
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C
3 calories/sec
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D
4 calories/sec
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Solution
The correct option is B 2 calories/sec Heat generated per sec P=V2R
For 5Ω : 10=V25⟹V=5√2 volts
Thus voltage across 4Ω, V′=44+6V=410×5√2=2√2 volts
∴ Heat generated per sec in 4Ω, P′=(V′)24=84=2 calories/sec