Question

In the circuit shown in the figure, the input voltage $V_i$ is $20V$, $V_{BE}=0V$ and $V_{CE}=0V$. The value of $I_B$ is given by

• A. $40\mu A$
• B. $25\mu A$
• C. $20\mu A$
• D. $40\mu A$

Answer 1

The correct option is D $40\mu A$

$V_i=I_B{R}_B+V_{BE}20=I_B\times \left(500\times {10}^3\right)+0I_B=\frac{20}{500\times {10}^3}=40\mu A$