Question

In the circuit shown in the following figure $E=10\text{V},R_1=2\text{ohm},R_2=3\text{ohm}$ and $R_3=6\text{ohm}$ and $L=5\text{henry}$ . The current $I_1$ just after pressing the switch $S$ is

(correct answer + 2, wrong answer - 0.50)

• A. $2.5\text{amp}$
• B. $2\text{amp}$
• C. $5/6\text{amp}$
• D. $5/3\text{amp}$

Answer 1

The correct option is B $2\text{amp}$

Just after closing of switch inductor behaves as open circuit. Equivalent circuit is shown $I_1=\frac{E}{R_1+R_2}=\frac{10}{2+3}=\frac{10}{5}=2\text{amp}$