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Question

In the circuit shown in the following figure, the switch is kept closed for a long time and then opened at t = 0.
The values of the current just before opening the switch (t=0) are, respectively.


A
34Aand1A
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B
76Aand52A
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C
1Aand76A
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D
1 A and 1 A
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Solution

The correct option is C 1Aand76A
at t=0
The inductor will be short,


i=3020+10A=1A

and current through inductor at t=0+

IL=1A

From the figure,

Applying KVL in outer loop.

30=(20+20)I+20i ....(i)

As the current through the inductor does not change instantaneously. The current the inductor will be 1 A at t = 0+

i=(I+1)

30=40I+20I+20

I=1060=16

Hence current,

i=I+1=16+1=76A

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