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Question

In the circuit shown, the 5 Ω resistance develops 45 Js1 of heat due to the flow of current through it. The current I is


A
4 A
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B
3 A
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C
2 A
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D
1 A
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Solution

The correct option is A 4 A


Given, Ht=45 Js1

From, the given circuit,

VAB=5I2=15I1

I2=3I1 .......(1)

Heat generated is,

H=I2Rt

Ht=I2R=V2ABR

45=V2AB5V2AB=32×52

VAB=3×5=15 V

I1=VAB15=1515=1 A

I2=3I1=3 A

I=I1+I2=1+3=4 A

<!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> Hence, (A) is the correct answer.

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