Question

In the circuit shown, the current in the $1\Omega$ resister is

• A. $1.3A,fromPtoQ$
• B. $0.13A,fromQtoP$
• C. $0A$
• D. $0.13A,fromPtoQ$

Answer 1

The correct option is B $0.13A,fromQtoP$

Connecting point Q to ground and by applying Kirchoff's law

Incoming current at Q=Byt going current from Q

$\frac{V+6}{3}+\frac{V}{I}=\frac{9-V}{5}V[\frac{1}{3}+\frac{1}{5}+1]=\frac{9}{5}-2V\left[\frac{5+3+15}{15}\right]=\frac{9}{5}-2V\left[\frac{23}{15}\right]=-\frac{1}{5}orV=-\frac{-3}{-23}V=-0.13V$

Thus, current in $1\Omega$ resistance is $0.13A$ from Q to P.