Question

In the circuit shown, voltage between terminals A and B is shown in graph. The maximum output voltage $V_0$ is

• A. $0.5V$
• B. $1V$
• C. $5V$
• D. $10V$

Answer 1

The correct option is C $5V$

Let us consider the positive and negative half cycles seperately.
Positive half cycle:


Current passes from A to B. There will be no current through the diode $D_1$ as it is reverse biased. Hence we can replace it with an open switch. While current passes through the diode $D_2$ and we can replace it with a closed switch.

Negative half cycle:


Current passes from B to A. There will be no current through the diode $D_2$ as it is reverse biased. Hence we can replace it with an open switch. While current passes through the diode $D_1$ and we can replace it with a closed switch.

If we observe carefully, both the cases are similar and the equivalent circuit diagram can be represented as shown below and we are required to find the maximum $V_0$


The maximum $V_0$ corresponds to the maximum alternating current which is $10V$.
$i_0=\frac{10}{(2+2)\times {10}^3}=\frac{1}{400}A$
Hence, $V_0=i_0\times 2\times {10}^3=\frac{1}{400}\times 2\times {10}^3$
$=5V$