In the closest packing of atoms A (radius : $r_{a}$ ), the radius of atom B that can be fitted into tetrahedral voids is:

0.155 r_{a}

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0.225 r_{a}

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0.414 r_{a}

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0.732 r_{a}

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Solution

The correct option is B $0.225 r_{a}$

In the closest packing of atoms A ( radius : $r_{a}$ ), the radius of atom B that can be fitted into radius of the tetrahedral void relative to the radius of the sphere is 0.225.

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Similar questions

A (radius : r_{a})

B

r is radius of the tetrahedral void

R is radius of the atoms in close packing

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