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Question

In the complex [Pt(py)4][PtCl4], the oxidation numbers of Pt atom in former and later part of the compound are respectively :

A
0 and 0
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B
+4 and +2
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C
+2 and +2
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D
0 and +4
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Solution

The correct option is C +2 and +2
To balance the -4 charges of chloride ions each platinum atom will exhibit +2 oxidation state as (py)4 has no charge.
Let the charge of Pt is x. As the compound is neutral, therefore, total charge is 0. Chlorine has -1 charge.
2x4=0
x=+2
IUPAC name of the given complex tetrapyridineplatinum(II) tetrachloroplatinate(II).

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