In the complex $[CoC l_{2} {(en)}_{2}] Br$ , the co-ordination number and oxidation state of cobalt are:

6 and +3

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3 and +3

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4 and +2

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6 and +1

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Solution

The correct option is A 6 and +3
$[C o C l_{2} (e n)_{2}] B r \Rightarrow [C o C l_{2} (e n)_{2}]^{+ 1}$
$= n - 2 = + 1$
$n = 3$
The co-ordination number is 6.
Oxidation state is 3.

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