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Question

In the construction of the bisector of a given angle, as shown in the figure below

ΔBEF ΔBDF by which congruence criterion?


A

SAS

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B

AAS

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C

SSS

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D

RHS

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Solution

The correct option is B SSS

BE = BD (Radii of the same arc)

EF = DF (Arcs of equal radii)

We note that, BF = BF (Common)

Therefore, ΔBEFΔBDF by SSS congruence rule.


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