In the construction of the bisector of a given angle, as shown in the figure below
ΔBEF ≅ ΔBDF by which congruence criterion?
The correct option is B SSS
BE = BD (Radii of the same arc)
EF = DF (Arcs of equal radii)
We note that, BF = BF (Common)
Therefore, ΔBEF≅ΔBDF by SSS congruence rule.