Question

In the coordination compound $K_4\left[Ni\right(CN{)}_4]$, the oxidation state of nickel is:

• A. -1
• B. 0
• C. 1
• D. 2

Answer 1

Answer: (B)

0

Consider the compound $K_4\left[Ni\right(CN{)}_4]$

Let oxidation state of Nickel be $x$

$(1\times 4)+x+(4\times -1)=0$

$\Rightarrow 4+x-4=0$

$\Rightarrow x=0$

Hence, in the given compound, the oxidation state of Nickel is zero.